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JEE Main 2026 Mathematics question

MathematicsQuadratic Equations and InequalitiesJEE Main 2026

Let a, b ∈ ℂ. Let α, β be the roots of the equation x² + ax + b = 0. If β − α = √11 and β² − α² = 3i√11, then (β³ − α³)² is equal to:

Answer: (B)

Solution

(β−α)(β+α) = 3i√11 gives β+α = 3i. Then αβ = [(α+β)²−(β−α)²]/4 = (−9−11)/4 = −5, and α²+β² =

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Question ID VK-015485