JEE Main 2026 Mathematics question
Let tanA, tanB, where A,B∈(−π/2,π/2), be the roots of the quadratic equation x²−2x−5=0. Then is equal to:
Answer: (C)
Solution
tanA+tanB=2, tanAtanB=−5, so tan(A+B)=2/6=1/3, giving cos(A+B)=3/√10
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