JEE Main 2026 Mathematics question
The product of all possible values of α, for which , is:
Answer: (C)
Solution
Expanding to second order gives [α²+(α+1)²+(α+2)²]/[2(α+1)²] = 2, leading to α²+2α−1=0. The product of roots is −1.
The product of all possible values of α, for which , is:
Expanding to second order gives [α²+(α+1)²+(α+2)²]/[2(α+1)²] = 2, leading to α²+2α−1=0. The product of roots is −1.