JEE Main 2026 Physics question
When one moves from a point 16 km below the earth's surface to a point 16 km above the earth's surface. The change in g is approximately α %. The value of α is . (Take radius of the earth = 6400 km.)
Answer: (B)
Solution
g(depth d) ≈ g(1−d/R); g(height h) ≈ g(1−2h/R). With d=h=16 km: Δg/g ≈ −h/R = −16/6400 = −0.0025, i.e. a 0.25% change.