JEE Main 2026 Physics question
A ray of light passing through an equilateral prism is having velocity 2.12×10⁸ m/s in the prism material, then the minimum angle of deviation is degrees.
Answer: (B)
Solution
n=c/v=3×10⁸/2.12×10⁸=1.415. Using n=sin((A+δm)/2)/sin(A/2) with A=60°: sin((60+δm)/2)=1.415×0.5=0.7075, giving (60+δm)/2≈45.04°, so δm≈30°.