JEE Main 2026 Physics question
From 18 m height above the ground a ball is dropped from rest. The height above the ground at which the magnitude of velocity equal the magnitude of acceleration (in the same set of units) due to gravity is m. (Take g=10 m/s² and neglect the air resistance)
Answer: 13
Solution
v=10 (matching g=10 numerically) gives fall distance d=v²/2g=100/20=5 m. Height above ground = 18−5 = 13 m.