JEE Main 2026 Physics question
A transverse wave on a string is described by y=3sin(36t+0.018x+π/4), where x,y are in cm and t in seconds. The least distance between the two successive crests in the wave is cm. (Nearest integer) (π=3.14)
Answer: 349
Solution
k=0.018 cm⁻¹. λ=2π/k=2(3.14)/0.018≈349 cm.