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JEE Main 2026 Chemistry question

ChemistryOrganic Chemistry - Some Basic Principles and TechniquesJEE Main 2026

In an estimation of sulphur by Carius method 0.2 g of the substance gave 0.6 g of BaSO₄. The percentage of sulphur in the substance is %. (Given molar mass in g mol⁻¹ S:32, BaSO₄:233)

Answer: 41

Solution

Moles BaSO₄ = 0.6/233 = 0.002575 = moles S. Mass S = 0.002575×32 = 0.0824 g. %S = (0.0824/0.2)×100 ≈ 41%.

Question ID VK-015556