JEE Main 2026 Chemistry question

One mole of phenol is treated with dilute HNO₃ at 298 K to give a mixture of products. The mixture is separated by steam distillation. The steam volatile compound (X) is separated. The increase in percentage of oxygen in (X) with respect to phenol is ×10⁻¹ %. (Given molar mass in g mol⁻¹ H:1, C:12, N:14, O:16)