JEE Main 2026 Chemistry question
The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below: A(g)⇌B(g)+C(g)
| 1/T (K⁻¹) | log₁₀Kp | |---|---| | 0.05 | 3.5 | | 0.06 | 2.5 | | 0.07 | 1.5 |
The magnitude of ΔH°/R calculated from the above data is . (Nearest integer)
Answer: 230
Solution
Slope of log Kp vs 1/T = (1.5−3.5)/(0.07−0.05) = −100 = −ΔH°/(2.303R). So ΔH°/R = 100×2.303 ≈ 230.