JEE Main 2026 Mathematics question
The eccentricity of an ellipse E with centre at the origin O is √3/2 and its directrices are x=±4√6/3. Let H : x²/a²−y²/b²=1 be a hyperbola whose eccentricity is equal to the length of semi-major axis of E, and whose length of latus rectum is equal to the length of minor axis of E. Then the distance between the foci of H is:
Answer: (D)
Solution
For E: a/e=4√6/3 gives a=2√2, and b=a√(1−e²)=√2. For H: eccentricity =2√2. Its latus rectum
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