JEE Main 2026 Mathematics question
If , x∈(0,1), then the value of x is:
Answer: (A)
Solution
LHS=x√2/√(1+2x²). If sinθ=√(1−x²) then cosθ=x, so RHS=x/√(1−x²). Equating and squaring: 2(1−x²)=1+2x², so x²=1/4 and x=1/2.
If , x∈(0,1), then the value of x is:
LHS=x√2/√(1+2x²). If sinθ=√(1−x²) then cosθ=x, so RHS=x/√(1−x²). Equating and squaring: 2(1−x²)=1+2x², so x²=1/4 and x=1/2.