JEE Main 2026 Mathematics question
The value of the integral is equal to:
Answer: (B)
Solution
The denominator is even, so the x³ term integrates to zero over [−1,1]. The rest is 2∫₀¹(x+1)/(x+1)²dx=2∫₀¹dx/(x+1)=2 ln2.
The value of the integral is equal to:
The denominator is even, so the x³ term integrates to zero over [−1,1]. The rest is 2∫₀¹(x+1)/(x+1)²dx=2∫₀¹dx/(x+1)=2 ln2.