JEE Main 2026 Physics question
A spring stretches by 2 mm when it is loaded with a mass of 200 g. From equilibrium position the mass is further pulled down by 2 mm and released. The frequency associated with the system and maximum energy in the spring are Hz and J, respectively. (Take g=10 m/s²)
Answer: (A)
Solution
k=mg/x=(0.2)(10)/0.002=1000 N/m. ω=√(k/m)=√5000, so f=ω/2π=5√50/π. The maximum
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