JEE Main 2026 Physics question
The electric potential as a function of x, y is given by V=5(x²−y²) V. The electric field at a point (2,3) m is V/m.
Answer: (A)
Solution
E⃗=−∇V=(−10x)î+(10y)ĵ. At (2,3): E⃗=−20î+30ĵ.
The electric potential as a function of x, y is given by V=5(x²−y²) V. The electric field at a point (2,3) m is V/m.
E⃗=−∇V=(−10x)î+(10y)ĵ. At (2,3): E⃗=−20î+30ĵ.