JEE Main 2026 Physics question
A square loop of side 2 cm is placed in a time varying magnetic field with magnitude as B=0.4 sin(300t) Tesla. The normal to the plane of loop makes an angle of 60° with the field. The maximum induced emf produced in the loop is mV.
Answer: (D)
Solution
EMF=A cos60°·|dB/dt|. |dB/dt|max=0.4×300=120 T/s and A=4×10⁻⁴ m². =4×10⁻⁴×0.5×120=0.024 V=24 mV.