JEE Main 2026 Physics question
Angle of minimum deviation is equal to the half of the angle of prism in an equilateral prism. The refractive index of the prism is .
Answer: (C)
Solution
A=60°, δ_min=30°. n=sin((A+δ)/2)/sin(A/2)=sin45°/sin30°=√2.
Angle of minimum deviation is equal to the half of the angle of prism in an equilateral prism. The refractive index of the prism is .
A=60°, δ_min=30°. n=sin((A+δ)/2)/sin(A/2)=sin45°/sin30°=√2.