JEE Main 2026 Chemistry question
An optically active alkyl bromide C₄H₉Br, reacts with ethanolic KOH to form major compound [A] which reacts with bromine to give compound [B]. Compound [B] reacts with ethanolic KOH and sodamide to give compound [C]. One molecule of water adds to compound [C] on warming with mercuric sulphate and dilute sulphuric acid at 333 K to form compound [D]. The functional group in compound D will be confirmed by:
Answer: (A)
Solution
The optically active bromide is 2-bromobutane. Elimination gives but-2-ene [A]; Br₂ gives 2,3-dibromobutane [B]; double
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