JEE Main 2026 Chemistry question
The number of compounds from the following which can undergo reaction with Br₂/KOH (alcoholic) to give respective products and these respective products can also be obtained separately by Gabriel phthalimide reaction is: benzamide (C₆H₅CONH₂); phenylacetamide (C₆H₅CH₂CONH₂); acetamide (CH₃CONH₂); N-ethylcyclohexanecarboxamide (C₆H₁₁CONHCH₂CH₃); N-methylpivalamide ((CH₃)₃CCONHCH₃); cyclohexanecarboxamide (C₆H₁₁CONH₂).
Answer: (C)
Solution
Br₂/KOH (Hofmann bromamide degradation) works only on primary amides RCONH₂, ruling out the two N-substituted amides. Benzamide would give aniline, an aromatic amine that Gabriel synthesis cannot
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account