JEE Main 2026 Chemistry question
In a closed flask at 600 K, one mole of X₂Y₄(g) attains equilibrium as given below: X₂Y₄(g)⇌2XY₂(g). At equilibrium, 75% X₂Y₄(g) was dissociated and the total pressure is 1 atm. The magnitude of Δ_rG° (in kJ mol⁻¹) at this temperature is . (Nearest Integer) (Given: R=8.3 J mol⁻¹K⁻¹; ln10=2.3, log2=0.3, log3=0.48, log5=0.69, log7=0.84)
Answer: 8
Solution
At equilibrium: 0.25 mol X₂Y₄ and 1.5 mol XY₂ (total 1.75). Partial pressures: 1/7 atm and 6/7 atm.
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