JEE Main 2026 Chemistry question
Decomposition of a hydrocarbon follows the equation k=(5.5×10¹¹ s⁻¹)e^(−28000 K/T). The activation energy of reaction is kJ mol⁻¹. (Nearest Integer) Given: R=8.3 J K⁻¹mol⁻¹
Answer: 232
Solution
Comparing with k=Ae^(−/RT): /R=28000 K, so =28000×8.3=232400 J/mol≈232 kJ/mol.