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JEE Main 2026 Mathematics question

MathematicsQuadratic Equations and InequalitiesJEE Main 2026

Let one root of the quadratic equation in x: (k²−15k+27)x²+9(k−1)x+18=0 be twice the other. Then the length of the latus rectum of the parabola y²=6kx is equal to:

Answer: (D)

Solution

With roots r and 2r: sum 3r = −9(k−1)/A and product 2r² = 18/A, where A=k²−15k+27.

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Question ID VK-015636