JEE Main 2026 Mathematics question
If the eccentricity e of the hyperbola , passing through (6, 4√3), satisfies 15(e²+1)=34e, then the length of the latus rectum of the hyperbola is:
Answer: (A)
Solution
15e²−34e+15=0 gives e=5/3 (>1), so b²=a²(e²−1)=16a²/9. Passing through (6,4√3): 36/a²−48/b²=1
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account