Let S= θ∈(−2π, 2π) : cosθ+1=√3 sinθ . Then _ S is equal to:

JEE Main 2026 Mathematics question

Not in JEE Main syllabus

Let S={θ∈(−2π, 2π) : cosθ+1=√3 sinθ}. Then is equal to:

Answer: (B)

The equation is equivalent to cos θ−√3 sin θ=−1, i.e. cos(θ+π/3)=−1/2, giving θ=π/3, −5π/3, and

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Question ID VK-015648