JEE Main 2026 Mathematics question
Let y=y(x) be the solution of the differential equation , x≥1. If y(1)=1, then the greatest integer less than y(√5) is .
Answer: 3
Solution
Dividing through and using 1/(x−√(x²−1))=x+√(x²−1), the equation is dy/dx+y/x=x+√(x²−1). With integrating factor x:
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