JEE Main 2026 Physics question
The two wires A and B of equal cross-section but of different materials are joined together. The ratio of Young's modulus of wire A and wire B is 20/11. When the joined wire is kept under certain tension the elongations in the wires A and B are equal. If the length of wire A is 2.2 m, then the length of wire B is m.
Answer: (C)
Solution
Same tension and area: Δl=Tl/(AY), so equal elongations give /=/. =/=2.2×11/20=1.21 m.