JEE Main 2026 Physics question
Two closed vessels of same volume are joined through a narrow tube and both vessels are filled with air of pressure 90 kPa and temperature 400 K. Keeping the temperature of one vessel constant at 400 K the second vessel temperature is raised to 500 K. The final pressure in the vessels is kPa.
Answer: (A)
Solution
Total moles conserved: 2P₀V/(R·400)=P'V/(R·400)+P'V/(R·500). So P'(1/400+1/500)=2(90)/400, giving P'=100 kPa.