JEE Main 2026 Physics question

PhysicsOscillationsJEE Main 2026

A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from x=A to x=A/√2 is sec.

Answer: (C)

Solution

Taking x=A cos ωt, x=A/√2 when ωt=π/4, so t=T/8=5/8 s.

Question ID VK-015671