JEE Main 2026 Chemistry question
An oxide of iron contains 69.9% iron, its empirical formula, is: (Given: Molar mass of Fe and O are 56 and 16 g mol⁻¹ respectively.)
Answer: (B)
Solution
Moles Fe=69.9/56=1.248; moles O=30.1/16=1.881. Ratio Fe:O=1:1.51≈2:3, so the formula is Fe₂O₃.