JEE Main 2026 Chemistry question
Consider the reaction X⇌Y at 300 K. If ΔH° and K are 28.40 kJ mol⁻¹ and 1.8×10⁻⁷ at the same temperature, then the magnitude of ΔS° for the reaction in J K⁻¹ mol⁻¹ is . (Nearest integer) (Given: R=8.3 J K⁻¹ mol⁻¹, ln 10=2.3, log 3=0.48, log 2=0.30)
Answer: 34
Solution
log K=log 1.8−7=(0.30+2×0.48−1)−7=−6.74, so ln K=−15.50. ΔG°=−RT ln
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