JEE Main 2026 Mathematics question
The sum of squares of all the real solutions of the equation is equal to .
Answer: 2
Solution
2x²+5x+3=(2x+3)(x+1) and x²+2x+1=(x+1)². Let u=+3). Then 1+u=4−2/u, so u²−3u+2=0, u=1 or 2. u=1 gives x=−2,
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