JEE Main 2026 Physics question
A gas balloon is going up with a constant velocity of 10 m/s. When this balloon reached a height of 75 m, a stone is dropped from it and balloon keeps moving up with the same velocity. The height of the balloon when the stone hits the ground is m. (Take g = 10 m/s²)
Answer: (D)
Solution
The stone starts with 10 m/s upward: 0=75+10t−5t², i.e. t²−2t−15=0, t=5 s. The balloon rises to 75+10×5=125 m.