JEE Main 2026 Physics question
The frequency of oscillation of a mass m suspended by a spring is ν₁. If the length of the spring is cut to half, the same mass oscillates with frequency ν₂. The value of ν₂/ν₁ is .
Answer: (C)
Solution
Halving the spring length doubles its spring constant. Since ν∝√k, ν₂/ν₁=√2.