JEE Main 2026 Physics question
A current carrying circular loop of radius 2 cm with unit normal is placed in a magnetic field, . If B₀ = 4×10⁻³ T and current I = 100√2 A, the torque experienced by the loop is Wb·A. (π = 3.14)
Answer: (D)
Solution
τ⃗=IA(n̂×B⃗). Here (î+k̂)×(3î+2k̂)=ĵ(1·3−1·2)=ĵ, so n̂×B⃗=(B₀/√2)ĵ. Then
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