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JEE Main 2026 Physics question

PhysicsMotion in a Straight LineJEE Main 2026

Two masses of 3.4 kg and 2.5 kg are accelerated from an initial speed of 5 m/s and 12 m/s, respectively. The distances traversed by the masses in the 5ᵗʰ second are 104 m and 129 m, respectively. The ratio of their momenta after 10 s is x/8. The value of x is .

Answer: 9

Solution

Distance in the nth second is u+a(2n−1)/2, so for n=5: 104=5+4.5a₁, giving a₁=22 m/s², and 129=12+4.5a₂, giving

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Question ID VK-015759