JEE Main 2026 Chemistry question
Match List-I with List-II. List-I (Mass of substance): A. 1.8 mg water, B. 9.8 mg sulphuric acid, C. 1.8 mg carbon, D. 5.85 mg salt (NaCl). List-II (Number of atoms): I. 2×10⁻⁴×, II. 1.5×10⁻⁴×, III. 3×10⁻⁴×, IV. 7×10⁻⁴×.
Answer: (C)
Solution
A: 1.8 mg H₂O=10⁻⁴ mol ×3 atoms=3×10⁻⁴ (III). B: 9.8 mg H₂SO₄=10⁻⁴ mol ×7 atoms=7×10⁻⁴
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