JEE Main 2026 Chemistry question
Solid carbon, CaO and CaCO₃ are mixed and allowed to attain equilibrium at T K. CaCO₃(s) ⇌ CaO(s) + CO₂(g) = 0.08 atm; C(s) + CO₂(g) ⇌ 2CO(g) = 2 atm. The partial pressure of CO is ×10⁻¹ atm
Answer: 4
Solution
From the first equilibrium p(CO₂)==0.08 atm. Then =p(CO)²/p(CO₂)=2 gives p(CO)²=0.16, so p(CO)=0.4 atm=4×10⁻¹ atm.