JEE Main 2024 Physics question
The de-Broglie wavelength associated with a particle of mass m and energy E is . The dimensional formula for Planck's constant is :
Answer: (B)
Solution
h = λ√(2mE), so [h] = [L][M · ML²T⁻² = [L][M L T⁻¹] = [ML²T⁻¹]. (Equivalently, E = hν gives [h] = [ML²T⁻²]/[T⁻¹].)