JEE Main 2024 Physics question
A capacitor of reactance 4√3 Ω and a resistor of resistance 4Ω are connected in series with an ac source of peak value 8√2 V. The power dissipation in the circuit is .................W.
Answer: 4
Solution
Z = √(R² + ²) = √(16 + 48) = 8 Ω. = 8√2/√2 = 8 V, so = 8/8 = 1 A. Power = I²_rms R = 1 × 4 = 4 W.