JEE Main 2024 Chemistry question
In the given TLC, the distance of spot A & B are 5 cm & 7 cm, from the bottom of TLC plate, respectively. value of B is x × 10⁻¹ times more than A. The value of x is . (The plate is 10 cm tall, with 1 cm at the bottom below the base line and 1 cm at the top above the solvent front.)
Answer: 15
Solution
The base line is 1 cm from the bottom and the solvent front is 8 cm from the base line (the front at 9 cm from the bottom). Spot A moved 5 − 1 = 4
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