JEE Main 2024 Chemistry question
When Δ = 30 kJ/mol and Δ = 75 J mol⁻¹ K⁻¹, then the temperature of vapour, at one atmosphere is K.
Answer: 400
Solution
At equilibrium ΔG = 0, so Δ = TΔ and T = 30 × 1000/75 = 400 K.
When Δ = 30 kJ/mol and Δ = 75 J mol⁻¹ K⁻¹, then the temperature of vapour, at one atmosphere is K.
At equilibrium ΔG = 0, so Δ = TΔ and T = 30 × 1000/75 = 400 K.