JEE Main 2024 Mathematics question

Mathematics Definite Integration JEE Main 2024

Let , 0 ≤ x ≤ 3, y ≥ 0, y(0) = 0. Then at x = 2, y″ + y + 1 is equal to :

(A)1Correct
(B)2
(C)√2
(D)1/2

Answer: (A)

Solution

Differentiating, √(1 − y′²) = y, so y′² = 1 − y² and dy/√(1 − y²) = ±dx. With y(0) = 0 and

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Question ID VK-016447