JEE Main 2024 Physics question
A proton, an electron and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as: a
Answer: (B)
Solution
λ = h/p = h/√(2mK). For the same energy K, λ ∝ 1/√m. The masses satisfy m_α > > , so λ_α < λ_p < λ_e.