JEE Main 2024 Physics question
The energy equivalent of 1 g of substance is:
Answer: (D)
Solution
E = mc² = 10⁻³ × (3 × 10⁸)² = 9 × 10¹³ J. In electron-volts E = 9 × 10¹³/(1.6 × 10⁻¹⁹) = 5.6 × 10³² eV = 5.6 × 10²⁶ MeV.
The energy equivalent of 1 g of substance is:
E = mc² = 10⁻³ × (3 × 10⁸)² = 9 × 10¹³ J. In electron-volts E = 9 × 10¹³/(1.6 × 10⁻¹⁹) = 5.6 × 10³² eV = 5.6 × 10²⁶ MeV.