Test SeriesFree PYQsExamsPricing

JEE Main 2024 Physics question

PhysicsElectrostatic Potential and CapacitanceJEE Main 2024

At the centre of a half ring of radius R = 10 cm and linear charge density 4n C m⁻¹, the potential is x π V. The value of x is .

Answer: 36

Solution

Every element of the half ring is at distance R from the centre, so V =

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-016496