JEE Main 2024 Chemistry question
Compare the energies of following sets of quantum numbers for multielectron system. (A) n = 4, ℓ = 1 (B) n = 4, ℓ = 2 (C) n = 3, ℓ = 1 (D) n = 3, ℓ = 2 (E) n = 4, ℓ = 0 Choose the correct answer from the options given below :
Answer: (D)
Solution
The energy is determined by comparing (n + ℓ): (A) 5, (B) 6, (C) 4, (D) 5, (E) 4. For the same value of (n + ℓ),
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