JEE Main 2024 Physics question
The total kinetic energy of 1 mole of oxygen at 27°C is [Use universal gas constant (R) = 8.31 J/mole K]
Answer: (A)
Solution
Oxygen is diatomic, so the total kinetic energy of one mole is (5/2)RT = 2.5 × 8.31 × 300 = 6232.5 J.