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JEE Main 2024 Physics question

PhysicsElectrostatic Potential and CapacitanceJEE Main 2024

Two charges of –4 μC and + 4 μC are placed at the point A(1, 0, 4) m and B(2, –1, 5) m located in an electric field V/cm. The magnitude of the torque acting on the dipole is Nm, where α = .

Answer: 2

Solution

Dipole moment p = q(ℓ) = 4 × 10⁻⁶(î − ĵ + k̂) C m, and E = 0.20 V/cm = 20 V/m î. τ = p ×

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Question ID VK-016587