JEE Main 2024 Physics question
The electric potential at the surface of an atomic nucleus (z = 50) of radius 9 × 10⁻¹³ cm is × 10⁶ V.
Answer: 8
Solution
V = Kze/r = (9 × 10⁹ × 50 × 1.6 × 10⁻¹⁹)/(9 × 10⁻¹⁵) = 8 × 10⁶ V.
The electric potential at the surface of an atomic nucleus (z = 50) of radius 9 × 10⁻¹³ cm is × 10⁶ V.
V = Kze/r = (9 × 10⁹ × 50 × 1.6 × 10⁻¹⁹)/(9 × 10⁻¹⁵) = 8 × 10⁶ V.