JEE Main 2024 Chemistry question
9.3 g of aniline is subjected to reaction with excess of acetic anhydride to prepare acetanilide. The mass of acetanilide produced if the reaction is 100% completed is × 10⁻¹ g. (Given molar mass in g mol⁻¹ N : 14, O : 16, C : 12, H : 1)
Answer: 135
Solution
Moles of aniline (M = 93) = 9.3/93 = 0.1. Acetanilide (C₆H₅NHCOCH₃, M = 135) formed = 0.1 × 135 = 13.5 g = 135 × 10⁻¹ g.